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11.5=16x+x^2
We move all terms to the left:
11.5-(16x+x^2)=0
We get rid of parentheses
-x^2-16x+11.5=0
We add all the numbers together, and all the variables
-1x^2-16x+11.5=0
a = -1; b = -16; c = +11.5;
Δ = b2-4ac
Δ = -162-4·(-1)·11.5
Δ = 302
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-\sqrt{302}}{2*-1}=\frac{16-\sqrt{302}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+\sqrt{302}}{2*-1}=\frac{16+\sqrt{302}}{-2} $
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